2x^2-450x+105=0

Solution for 2x^2-450x+105=0 equation:

2x^2-450x+105=0

a = 2; b = -450; c = +105;
Δ = b2-4ac
Δ = -4502-4·2·105
Δ = 201660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{201660}=\sqrt{4*50415}=\sqrt{4}*\sqrt{50415}=2\sqrt{50415}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-450)-2\sqrt{50415}}{2*2}=\frac{450-2\sqrt{50415}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-450)+2\sqrt{50415}}{2*2}=\frac{450+2\sqrt{50415}}{4}
$